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integral of 0 to π sin ¹°°xcos??x dx

Pradeeep Anand , 11 Years ago
Grade 11
anser 1 Answers
Sher Mohammad

Last Activity: 11 Years ago


I=?sin ¹°°xcosx=sin ¹°°x?cosxdx-?cosx?((dsin ¹°°x)/dx)dx
=sin ¹°°xsinx -100?sin ¹°°xcosx
I+100I = sin ¹°°xsinx
I =1/(101)(sin(x)^101)(between 0 top)
=0

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Sher Mohammad,
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B.Tech.
IIT Delhi.

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