if i=∫2/x (x lnx ) (ln x) 3 dx = Ax lnx (lnx)^2- B x^ ln x +C, then A/B is equal to :

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Aditya Gupta · Answer

hello jahnvi, this is a very ez ques. simply put y= lnx so that x= e^y and dx= xdy so, i=∫2/x (x lnx ) (ln x) 3 dx = i=∫2e^(y^2)*y^3 dy now put y^2= t so 2ydy= dt so i = ∫t*e^t dt = e^t*(t – 1) + C (integration by parts) = e^(y^2)*(y^2 – 1) + C = x^lnx*(ln^2x – 1) + C = x lnx (lnx)^2 – x^ ln x +C so A= B= 1 or A/B = 1 kindly approve :))

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if i=∫2/x (x lnx ) (ln x) 3 dx = Ax lnx (lnx)^2- B x^ ln x +C, then A/B is equal to :

if i=∫2/x (x^lnx) (ln x)³dx = Ax^lnx(lnx)^2- B x^^{ln x}+C, then A/B is equal to :

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if i=∫2/x (x lnx ) (ln x) 3 dx = Ax lnx (lnx)^2- B x^ ln x +C, then A/B is equal to :

if i=∫2/x (xlnx) (ln x)3 dx = Axlnx(lnx)^2- B x^ln x+C, then A/B is equal to :

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if i=∫2/x (x^lnx) (ln x)³dx = Ax^lnx(lnx)^2- B x^^{ln x}+C, then A/B is equal to :