If ?[(g(x)*(g’(x)/(-2)*(d(1/(g’(x)) 2 )/dx) dx = d(1/(g’(x)) 2 )/dx – g(x)/(g’(x)), find the value of g(sin x)/(px^2) at x = 1/(2p). The answer given is 2, but how to find g(x) first?

Question

If ?[(g(x)*(g’(x)/(-2)*(d(1/(g’(x)) 2 )/dx) dx = d(1/(g’(x)) 2 )/dx – g(x)/(g’(x)), find the value of g(sin x)/(px^2) at x = 1/(2p). The answer given is 2, but how to find g(x) first?

Aaron Stone · Answer

The question mark in the above question is actually integral sign.

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If ?[(g(x)(g’(x)/(-2)(d(1/(g’(x)) 2 )/dx) dx = d(1/(g’(x)) 2 )/dx – g(x)/(g’(x)), find the value of g(sin x)/(px^2) at x = 1/(2p). The answer given is 2, but how to find g(x) first?

If ?[(g(x)(g’(x)/(-2)(d(1/(g’(x))²)/dx) dx = d(1/(g’(x))²)/dx – g(x)/(g’(x)), find the value of g(sin x)/(px^2) at x = 1/(2p).

The answer given is 2, but how to find g(x) first?

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