Define a function h : [0, 1] ? [-1, 1] as h(x) = sin p( 2x 2-1 ). Using Inverse function Theorem, find v -1/ 2. Hint: Show that h(x) is a bijective function. d -1 dx h at x = 0 , x =

goes from [-1,1]. As x belongs to [0,1],= Take f(x) = f(y) for some x,y in domain, At x=0, Answer = 0 THerefore, x = y. Also, for all b in range, there is some a in the domain. Hence, h(x) is a bijective function. = It implies that