Sir,

how to integrate

dx/[k-m{(2nx)^1/2}]

from 0 to x

k,m&n are constants

Dear aman

 _o∫^xdx/[k-m√2nx]

we can also wrote

I = 1/m√2n _o∫^xdx/[(k/m√2n)-√x]

    =  1/m√2n _o∫^xdx/[a-√x]            where a =(k/m√2n)

 I= 1/m√2n _o∫^x[a+√x]dx/[a-x]

  I= 1/m√2n _o∫^x[a]dx/[a-x]  +  1/m√2n _o∫^x[√x]dx/[a-x]

first part u can easly calculate

for second part  

 I2 = _o∫^xxdx/√x[a-x]

put √x = t

         dx = 2tdt

I2 = _o∫^√x2t²dt/[a-t²]

this is also a standard form

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