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Sir,
how to integrate
dx/[k-m{(2nx)^1/2}]
from 0 to x
k,m&n are constants
Dear aman
o∫xdx/[k-m√2nx]
we can also wrote
I = 1/m√2n o∫xdx/[(k/m√2n)-√x]
= 1/m√2n o∫xdx/[a-√x] where a =(k/m√2n)
I= 1/m√2n o∫x[a+√x]dx/[a-x]
I= 1/m√2n o∫x[a]dx/[a-x] + 1/m√2n o∫x[√x]dx/[a-x]
first part u can easly calculate
for second part
I2 = o∫xxdx/√x[a-x]
put √x = t
dx = 2tdt
I2 = o∫√x2t2dt/[a-t2]
this is also a standard form
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