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∫√tan x

∫√tan x

Grade:12

1 Answers

Menka Malguri
39 Points
10 years ago

Let tanx=t2,..................(1)

then differentiating both sides,we get,

sec2x dx=2t dt

(1+tan2x) dx=2t dt

(1+t4) dx=2t dt.................from(1)

dx=[2t/(1+t4)] dt

now,

∫√tanx

=∫√(t2).[2t/(1+t4)] dt

=∫[2t2/(1+t4)] dt

and solve further.

 

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