Flag Integral Calculus> maximum value...
question mark

find the maximim value of the integral (3/4 -x-X^2)dx lim b to a b is greater than a

pritam samanta , 14 Years ago
Grade 12
anser 1 Answers
Jitender Singh

Last Activity: 10 Years ago

Ans:
I = \int_{b}^{a}(\frac{3}{4}-x-x^{2})dx
I = (\frac{3x}{4}-\frac{x^{2}}{2}-\frac{x^{3}}{3})_{b}^{a}
I = \frac{3(a-b)}{4}-\frac{a^{2}-b^{2}}{2}-\frac{a^{3}-b^{3}}{3}
I = \frac{b(4b^{2}+6b-3)-a(4a^{2}+6a-3)}{12}
b>a
b = a + h, h\geq 0
I = \frac{(a+h)(4(a+h)^{2}+6(a+h)-3)-a(4a^{2}+6a-3)}{12}
I = \frac{4h^{3} + (12a+6)h^{2} + (12a^{2}+12a-3)h }{12}
\frac{\partial I}{\partial h} = \frac{12h^{2} + 2(12a+6)h + (12a^{2}+12a-3) }{12}= 0
Find ‘h’ from here:
12h^{2} + 2(12a+6)h + (12a^{2}+12a-3) = 0
h = \frac{-2(12a+6)\pm \sqrt{288}}{24}
h = -a + \frac{\sqrt{2}-1}{2}
b = h +a = \frac{\sqrt{2}-1}{2}
Thanks & Regards
Jitender Singh
IIT Delhi
askIITians Faculty

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...