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xd2y/dx2 = (dy/dx)2
i getting problem insolving ∫1/lnxdx
Hi manoj jangra
∫1/lnxdx
you can put lnx=t
x=et
dx=e^t dt
Now ∫ t-1et dt
now expand the series et
∫(1+t+t2/!2+t3/!3+.....)/t dt
Now intigrate
= lnt +t +t2/2*!2+t3/3*!3.......
=ln t +∑tk/k*!k where k =1 to infinity
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation. All the best manoj. Regards, Askiitians Experts Badiuddin
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