xd2y/dx2 = (dy/dx)2i getting problem insolving ∫1/lnxdx

Hi manoj jangra

∫1/lnxdx

you can put lnx=t

        x=e^t

  dx=e^t dt

Now  ∫ t^-1e^t  dt

            ^{now expand the series} e^t

     ∫(1+t+t²/!2+t³/!3+.....)/t dt

     Now intigrate

  =  lnt  +t +t²/2*!2+t³/3*!3.......

   =ln t +∑t^k/k*!k      where k =1 to infinity