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xd 2 y/dx 2 = (dy/dx) 2 i getting problem insolving ∫1/lnxdx

xd2y/dx2 = (dy/dx)2


i getting problem insolving ∫1/lnxdx

Grade:12

1 Answers

Badiuddin askIITians.ismu Expert
147 Points
12 years ago

Hi manoj jangra

∫1/lnxdx

you can put lnx=t

        x=et

  dx=e^t dt

Now  t-1edt

            now expand the series et

     ∫(1+t+t2/!2+t3/!3+.....)/t dt

     Now intigrate

  =  lnt  +t +t2/2*!2+t3/3*!3.......

   =ln t +∑tk/k*!k      where k =1 to infinity

 


Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE preparation. All the best manoj.
 
 

Regards,

Askiitians Experts

Badiuddin

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