Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

plz solve for me in detail this question: Q.integrate 2^x.e^x wrt x

plz solve for me in detail this question:

Q.integrate 2^x.e^x wrt x

Grade:

2 Answers

Ashwin Muralidharan IIT Madras
290 Points
9 years ago

Hi Nishad,

 

Let I = ∫2xexdx.

Integrate by parts, we get

I = 2xex - ∫2xexlog2dx + C

So I = 2xex - log2*I + C

So (1+log2)I = 2xex + C

So I = 2xex/(1+log2) + C'

Or I = 2xex/log(2e) + C'

 

That is the integral of the above function.

 

Best Regards,

Ashwin (IIT Madras).

Godfrey Classic Prince
633 Points
9 years ago

Dear nishad bagwe,

The Integration of ∫2xex dx is 2[ex(x-1) + c]

Let I = 2∫x.ex dx

      Using the integration by parts method,

Take u = x               v =ex dx

        du = dx           dv=ex

Now sustitute them by the formula,

∫udv = uv - ∫vdu

Now you will get this answer .

 

Hope this helped you immensely..

All the Very Best & Good Luck to you ..

Regards,

AskIITians Expert

Godfrey Classic Prince

IIT-M

Please approve my answer if you liked it by clicking on "Yes" given below...!!!Smile

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free