∫dx/(ex + 4e-x) = f (x) + c then f (x) is equal to
∫dx/(ex + 4e-x)
=∫exdx/(ex2 + 4)
=1/2∫2exdx/(ex2 + 4)
=1/2 log [ex2 + 4]+c
therefore,
fx= 1/2 log [ex2 + 4]
plz approve if u like..
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