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Integrate (1-tanx)dx(1+tanx)

Aparna Tiwari , 14 Years ago
Grade 12
anser 1 Answers
vikas askiitian expert

Last Activity: 14 Years ago

I=(1-tanx)/1+tanx) dx

I={cosx-sinx/sinx+cosx}dx

on putting sinx+cosx=t

         (cosx-sinx)dx = dt

I=dt/t

 =logt +c

 =logsinx+cosx  + c

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