find the integral of  1-x^4/1-x

dear hsm

1-x⁴ = (1-x)(1+x)(1+x²)

so 1-x⁴/1-x = 1+x+x²+x³

Integration would me x+x²/2+x³/3+x⁴/4

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1-x^4/1-x   =(1-x^2)(1+x^2)/1-x)=(1-x)(1+x)(1+x^2)/1-x=(1+x)(1+x^2)

   value of integral is x^4/4 +x^3/3 +x^2/2 +x +c