∫ (1+cos4x ) / (cot x – tan x ) dx , plz answer asap, thank you

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Arun · Answer

On Solving the equation we get , {cos4x+1}/{cotx - tanx} = (2cos 2 2x)(sinx.cosx)/(cos 2 x - sin 2 x) = cos2x.sin2x = sin4x/2 On Integrating we get , -cos4x/8 + C

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∫ (1+cos4x ) / (cot x – tan x ) dx , plz answer asap, thank you

∫ (1+cos4x ) / (cot x – tan x ) dx , plz answer asap, thank you

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