0 to pi integral of log(sin^2x)dx.Solve this plz and tell me any trick to do it in a easy way

To solve this question you can use by parts formula this one lasted that this formula states that integral ffx in 2 G of x

Used by parts formula this formula states thatIntegral f(x).g(x) = f(x).int.g(x)dx - int f`(x).[int.g(x)dx]dx....Here f(x) is the first function and g(x) is the second function..Priority order of taking first function is ILATE..I - inverse trigonometric functionL - logarithmic functionA - algebraic functionT - trigonometric functionE - exponential..Here f(x) is log(sin^2x) and g(x) = 1..Also f`(x) is differentiation of first function.. You will definitely get the ans...Hope you have understood this