Flag Integral Calculus> 0 ∫ 1 (1+e -x^2 )dx=?
question mark

0∫1(1+e-x^2)dx=?

UTKARSH CHOUHAN , 9 Years ago
Grade 12
anser 1 Answers
jagdish singh singh

Last Activity: 9 Years ago

\hspace{-0.8 cm}$ Given $\bf{\int_{0}^{1}(1+e^{-x^2})dx = 1+\int_{0}^{1}e^{-x^2}dx\;,}$ Here we can not find\\\\ antiderivative of that Integrant in terms of elementry function.\\\\ So Here we can only find Range of $\bf{I.\;\; }$\\\\So $\bf{e^{-x}<e^{-x^2}<1\Rightarrow \int_{0}^{1}e^{-x}dx <\int_{0}^{1}e^{-x^2}dx<\int_{0}^{1}1dx}$\\\\ So we get $\bf{\left(1-\frac{1}{e}\right)<\int_{0}^{1}e^{-x^2}dx<1\Rightarrow \left(2-\frac{1}{e}\right)<1+\int_{0}^{1}e^{-x^2}dx<2}$

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...