Grade 12Physical Chemistry
A solution contains 16g of methanol and 90g of water the mole fraction of methanol in the solution is?
A solution contains 16g of methanol and 90g of water the mole fraction of methanol in the solution is?
2 Answers
Arun
moles of solute = 16 g / 32 g / mole = 0.50 moles
moles of solvent = 90.0 g / 18 g / mol = 5.0 moles
total number of moles of solute + solvent = 5.50 moles
mole fraction of the methanol = 0.50 / 5.50 = 0.1
moles of solvent = 90.0 g / 18 g / mol = 5.0 moles
total number of moles of solute + solvent = 5.50 moles
mole fraction of the methanol = 0.50 / 5.50 = 0.1
Khimraj
Methanol = CH4 O or CH3 OH
molar mass of methanol: 12+4+16=32
=> 16 gram = 0.5 moles
90 grams of water => 5 mole of water as molar mass of water is 18.
total number of moles in the solution = 5.5
so molar fraction of methanol in the solution = 0.5 /5.5 = 1/11
molar mass of methanol: 12+4+16=32
=> 16 gram = 0.5 moles
90 grams of water => 5 mole of water as molar mass of water is 18.
total number of moles in the solution = 5.5
so molar fraction of methanol in the solution = 0.5 /5.5 = 1/11
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