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Grade 11Physical Chemistry

A man standing in front of a mountain beats a drum at regular intervals. The rate of drumming is generally increased and he finds that the echo is not heard distinctly when the rate becomes 40 per minute. He then moves nearer to the mountain by 90 m and finds that echo is again not heard when the drumming rate becomes 60 per minute. Find the velocity of sound?

Profile image of ANSHAR
7 Years agoGrade 11
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1 Answer

Profile image of Arun
7 Years ago
For not hearing the echo the time interval between the beats of drum must be equal to time of echo.                    Þ 
t1=2dv=6040=32
                 ...... (i)                    and 
t2=2(d90)v=6060=1
                    Þ 
2d180=v
                   ...... (ii)                    Form (i), we get
2d=32v
. Substituting in (ii), we get                    Þ 
32v180=v
 Þ 
180=v2
 Þ 
v=360ms1
                    Þ 
2(d)360=32
 Þ 
d=270m