Sam Rock
Last Activity: 6 Years ago
Let,
3µF=C1
2µF=C2
4µF=C3
6µF=C4
5µF=C5
then, According to the diagram C5 will no work. because wheatston bridge is being formed
therefore, C2 and C3 are in series
1/Ceq=1/C2+1/C3
1/Ceq=1/2µF+1/4µF
therefore, Ceq=(4/3)µF
AND, C1 and C4 Are also in series,
then 1/Ceq1=1/C1=1/C4
therefore Ceq1=2µF
And Ceq And Ceq1 Are in parallel
therefore, C=Ceq=Ceq1
C=(3/4)+2
therefore C=(11/4)µF
eqivalent capacitance between points A and B is (11/4)µF