Electrostatics> TWO POSITIVE POINT CHARGES PLACED AT A DI...

TWO POSITIVE POINT CHARGES PLACED AT A DISTANCE ‘b’ APART HAVE SUM Q.FOR WHAT VALUES OF THE CHARGES IS THE COULOMB FORCE BETWEEN THEM MAXIMUM?

Bharat Makkar , 11 Years ago

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2 Answers

siddharth gupta

METHOD 1:

LET THE CHARGES ON THE TWO CHARGED PARTICLES BE Q₁AND Q₂

ELECTROSTATIC FORCE BETWEEN THEM=K(Q₁)(Q₂)/b²

USING A.M-G.M INEQUALITY FOR Q₁Q₂ TO BE MAXIMUM , Q₁=Q₂

i.e Q₁=Q₂=Q/2.

METHOD 2:

LET THE CHARGES BE Q-X AND X.

F=K(x)(Q-x)/b²

find dF/dx and put it equal to 0 i.eK/b²(Q-2x)=0

i.e Q=2x i.e Q/2=x.

WITH REGARDS

SIDDHARTH GUPTA

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Last Activity: 11 Years ago

Bharat Makkar

THANKS!

Last Activity: 11 Years ago

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Electrostatics> TWO POSITIVE POINT CHARGES PLACED AT A DI...

TWO POSITIVE POINT CHARGES PLACED AT A DISTANCE ‘b’ APART HAVE SUM Q.FOR WHAT VALUES OF THE CHARGES IS THE COULOMB FORCE BETWEEN THEM MAXIMUM?

Bharat Makkar , 11 Years ago

siddharth gupta

Bharat Makkar

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