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Grade: 12
        
Two equally charged identical metal spheres A and B repel each other with a force F another identical uncharged sphere is touched to A and then placed midway between A nad B.The net foce on C is in the direction?????
 
2 years ago

Answers : (1)

Ravneet
104 Points
							
THEORY
  • let two metal sphere are given charge q 
  • now an uncharged identical sphere is touched with A . after touching sphere A and C will get new charge 
  • new charge = (charge on A + charge on C ) / 2
  • new charge on A = new charge on B = q/2 
NOW, sphere C with charge q/2 is placed in midway between sphere A (with charge q/2 ) and sphere B (with charge q)
Force on C due to B = KQ2/2R2     WHERE R is the distance between B and C  (greater in magnitude )
Force on C due to A = KQ2/4R2     WHERE R is the distance between A and C 
Net force =  Repulsion Force on C due to B  –  Repulsion  Force on C due to A
after solving 
Net force = KQ2/4R2 
REMEMBER: if we calculate force between A and B when charge C is not there it will be KQ2/(2R)2 = F 
so we can say Net force = F ( toward A )
becouse Repulsion force of B on C is greater 
 
2 years ago
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Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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