Ravneet
Last Activity: 6 Years ago
THEORY
- let two metal sphere are given charge q
- now an uncharged identical sphere is touched with A . after touching sphere A and C will get new charge
- new charge = (charge on A + charge on C ) / 2
- new charge on A = new charge on B = q/2
NOW, sphere C with charge q/2 is placed in midway between sphere A (with charge q/2 ) and sphere B (with charge q)
Force on C due to B = KQ2/2R2 WHERE R is the distance between B and C (greater in magnitude )
Force on C due to A = KQ2/4R2 WHERE R is the distance between A and C
Net force = Repulsion Force on C due to B – Repulsion Force on C due to A
after solving
Net force = KQ2/4R2
REMEMBER: if we calculate force between A and B when charge C is not there it will be KQ2/(2R)2 = F
so we can say Net force = F ( toward A )
becouse Repulsion force of B on C is greater
