Please please IItians help.I posted many questions of electrostatic but don't get answer of any.Please please help me.Please all forum experts explain this question (given in attachment) in detail. Please.

Given that mass of particle m = 10mg
Charge 1 = – 0.01μC
A = 100cm² Let potential = V
The Equation capacitance C = 0.04/2 = 0.02μF
The particle may be in equilibrium, so that the wt. of the particle acting down ward, must be balanced by the electric force acting up ward.

∴ qE = Mg
Electric force = qE = q(V/d)

where V – Potential, d – separation of both the plates.

Now put qE = mg

You will get answer as 43 MV

Then you will get answer approx 43