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Given that mass of particle m = 10mgCharge 1 = – 0.01μCA = 100cm2 Let potential = VThe Equation capacitance C = 0.04/2 = 0.02μFThe particle may be in equilibrium, so that the wt. of the particle acting down ward, must be balanced by the electric force acting up ward.
∴ qE = MgElectric force = qE = q(V/d)
where V – Potential, d – separation of both the plates.
Now put qE = mg
You will get answer as 43 MV
Then you will get answer approx 43
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