Please explain question no. 23 in the attached image???
Rabiza Sohail Azmi , 7 Years ago
Grade 12
1 Answers
Vikas TU
Last Activity: 7 Years ago
Dear Student, The capacitance finally is Ceff. Let the K finally is keff Ceff=keffe0A/D
For the above 2 dielectrics they are in series. effective capacitance of the above two series connected dieelectrics is 1/C1 = D/k1e0A + D/k2e0A =>C1=e0A(k1k2)/D(k1+k2)
C2= Capacitance of the below dieelectric =2k3e0A/D Ceff= C1+C2 =e0A(k1k2/(k1+k2) + 2k3)/D keff=(k1k2/(k1+k2) + 2k3) Answer is C.
Cheers!!
Regards,
Vikas (B. Tech. 4th year Thapar University)
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