let mass of both the charges is m and charge on both the charges is q
take a sphere which is at height div two forces act on it
force of gravitation in downword direction and electrostatic force in downward direction hence net downward direction is qe+mg/m hence accelaration is qe/m+g hence
div=1/2(g+qe/m)t^2
let t is time taken by small sphere in travelling distance
l=vt , t=l/v
let x is distance travelled by second sphere
forces acting on it
force of gravitation downward and electrostatic force upwards hence net acceleration in downward direction is( g-qe/m)
X=1/2(g-qe/m)t^2
height at this instant is h2-x
x=gl^2/v^2-div
hence height is h2-(gl^2/v^2 how can you consider uniform electric field
let mass of both the charges is m and charge on both the charges is q
take a sphere which is at height div two forces act on it
force of gravitation in downword direction and electrostatic force in downward direction hence net downward direction is qe+mg/m hence accelaration is qe/m+g hence
div=1/2(g+qe/m)t^2
let t is time taken by small sphere in travelling distance
l=vt , t=l/v
let x is distance travelled by second sphere
forces acting on it
force of gravitation downward and electrostatic force upwards hence net acceleration in downward direction is( g-qe/m)
X=1/2(g-qe/m)t^2
height at this instant is h2-x
x=gl^2/v^2-div
hence height is h2-(gl^2/v^2 how can you consider uniform electric field
yash , 7 Years ago
Grade 12
