let mass of both the charges is m and charge on both the charges is qtake a sphere which is at height h1 two forces act on itforce of gravitation in downword direction and electrostatic force in downward direction hence net downward direction is qe+mg/m hence accelaration is qe/m+g henceh1=1/2(g+qe/m)t^2let t is time taken by small sphere in travelling distancel=vt , t=l/vlet x is distance travelled by second sphereforces acting on itforce of gravitation downward and electrostatic force upwards hence net acceleration in downward direction is( g-qe/m)X=1/2(g-qe/m)t^2height at this instant is h2-xx=gl^2/v^2-h1hence height is h2-(gl^2/v^2 how can you consider uniform electric field

yash , 6 Years ago

Grade 12