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let mass of both the charges is m and charge on both the charges is q

take a sphere which is at height div two forces act on it

force of gravitation in downword direction and electrostatic force in downward direction hence net downward direction is qe+mg/m hence accelaration is qe/m+g hence

div=1/2(g+qe/m)t^2

let t is time taken by small sphere in travelling distance

l=vt , t=l/v

let x is distance travelled by second sphere

forces acting on it

force of gravitation downward and electrostatic force upwards hence net acceleration in downward direction is( g-qe/m)

X=1/2(g-qe/m)t^2

height at this instant is h2-x

x=gl^2/v^2-div

hence height is h2-(gl^2/v^2 how can you consider uniform electric field

yash , 7 Years ago
Grade 12
anser 0 Answers
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