Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that (E = electric field, V = potential)? OPTIONS: E A E B ,V A B E A E B ,V A V B E A B ,V A B E A B ,V A V B

Question

Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that (E = electric field, V = potential)? OPTIONS: E A >E B ,V A B E A >E B ,V A >V B E A B ,V A B E A B ,V A >V B

Eshan · Answer

Dear student, Since the density of field lines is greater at point A than at B, . Since the electric field along the line joining in A and B is from B to A, the point B is at higher potential. Hence .

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Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that (E = electric field, V = potential)? OPTIONS: E A >E B ,V A B E A >E B ,V A >V B E A B ,V A B E A B ,V A >V B

Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that(E = electric field, V = potential)?
OPTIONS:

E_A>E_B,V_A_B

E_A>E_B,V_A>V_B

E_A_B,V_A_B

E_A_B,V_A>V_B

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Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that (E = electric field, V = potential)? OPTIONS: E A >E B ,V A B E A >E B ,V A >V B E A B ,V A B E A B ,V A >V B

Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that(E = electric field, V = potential)?OPTIONS: EA>EB,VAB EA>EB,VA>VB EAB,VAB EAB,VA>VB

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Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that(E = electric field, V = potential)?
OPTIONS:

E_A>E_B,V_A_B

E_A>E_B,V_A>V_B

E_A_B,V_A_B

E_A_B,V_A>V_B