Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that(E = electric field, V = potential)?

OPTIONS:

• E_A>E_B,V_AB
• E_A>E_B,V_A>V_B
• E_AB,V_AB
• E_AB,V_A>V_B

Dear student,

Since the density of field lines is greater at point A than at B,.

Since the electric field along the line joining in A and B is from B to A, the point B is at higher potential. Hence.