Figure shows some of the electric field lines corresponding to an electric field. The figure suggests that(E = electric field, V = potential)?OPTIONS: EA>EB,VAB EA>EB,VA>VB EAB,VAB EAB,VA>VB

Dear student,

Since the density of field lines is greater at point A than at B,.

Since the electric field along the line joining in A and B is from B to A, the point B is at higher potential. Hence.