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Determine the potential difference across the plates of capacitor C1 of the network shown in figure.Assume E2>E1.

Vishakha Chourasia , 10 Years ago
Grade 12
anser 3 Answers
SHIVANSHU

Last Activity: 10 Years ago

replace by a single battery of e.m.f =E2-E1. now the cap.s r in series. in series same charge implaies same capacitance. same capacitance implies same potential difference.
now, sum of P.D. = E2-E1. thus P.D. across each cap = (E2-E1)/2
Plz reply back if the ans is correct or not.

Shreyansh Jain

Last Activity: 8 Years ago

By Kirchoff`s voltage rule-V1 + V2 = q/c1 + q/c2 = E2 - E1 V1=q/c1 V2=q/c2V2=V1*c1/c2So V1(1+(c1/c2))=E2-E1V1= (E2-E1)*c2/(c1+c2)

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the solution to your question.
 
Applying Kirchoff’s voltage rule-
E1 + q/C1 – E2 + q/C2 = 0
or, q = (E2 – E1)C1C2/(C1 + C2)
Hence, V1 = q/C1 = (E2 – E1)C2/(C1 + C2)
 
Thanks and regards,
Kushagra

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