Consider uniform electric field E=3*10^3 I ,calculate the flux of the field through a square of area 10 cm^2 when 1)its plane is parallel to y-z plane 2)the normal to its plane makes a 60° angle with the x axis

Question

Khimraj · Answer

E = 3*10 3 A = 10*10 -4 , i) = 0 then flux = EAcos = 3 units ​ii) = 60 then flux = EAcos = 3/2 units Hope it clears. If you like anser then please approve it.

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Consider uniform electric field E=3*10^3 I ,calculate the flux of the field through a square of area 10 cm^2 when 1)its plane is parallel to y-z plane 2)the normal to its plane makes a 60° angle with the x axis

Consider uniform electric field E=3*10^3 I ,calculate the flux of the field through a square of area 10 cm^2 when
1)its plane is parallel to y-z plane
2)the normal to its plane makes a 60° angle with the x axis

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Consider uniform electric field E=3*10^3 I ,calculate the flux of the field through a square of area 10 cm^2 when 1)its plane is parallel to y-z plane 2)the normal to its plane makes a 60° angle with the x axis

Consider uniform electric field E=3*10^3 I ,calculate the flux of the field through a square of area 10 cm^2 when1)its plane is parallel to y-z plane2)the normal to its plane makes a 60° angle with the x axis

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Consider uniform electric field E=3*10^3 I ,calculate the flux of the field through a square of area 10 cm^2 when
1)its plane is parallel to y-z plane
2)the normal to its plane makes a 60° angle with the x axis