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# Consider uniform electric field E=3*10^3 I ,calculate the flux of the field through a square of area 10 cm^2 when1)its plane is parallel to y-z plane2)the normal to its plane makes a 60° angle with the x axis

Khimraj
3007 Points
3 years ago
E = 3*103 A = 10*10-4,
i) $\theta$ = 0
then flux = EAcos$\theta$ = 3 units
​ii) $\theta$ = 60
then flux = EAcos$\theta$ = 3/2 units
Hope it clears. If you like anser then please approve it.