An Electric field E=yi^+xj^N/C. The work done in moving a 1C charge from r=2i^+2j^ to r=4i^+j^

Question

Vikas TU · Answer

Dear Student,
We here calculate the work by sequence in x and y direction
as Work is a scalr quantity.
W=q∫Edx
=>W done in the x direction of the axis=1∫_2^4ydx
=2y
W=q∫Edy
=>W done in the y direction of the axis=-x

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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An Electric field E=yi^+xj^N/C. The work done in moving a 1C charge from r=2i^+2j^ to r=4i^+j^

An Electric field E=yi^+xj^N/C. The work done in moving a 1C charge from r=2i^+2j^ to r=4i^+j^

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An Electric field E=yi^+xj^N/C. The work done in moving a 1C charge from r=2i^+2j^ to r=4i^+j^

An Electric field E=yi^+xj^N/C. The work done in moving a 1C charge from r=2i^+2j^ to r=4i^+j^

1 Answers

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