An electric field E=(20i ^ + 30j ^ ) N/C exists i

Question

An electric field E=(20i^ + 30j^) N/C exists in space. If electric potential at origin is taken to be 50 V, then electric potential at (2m,2m) is?

Arun · Accepted Answer

Change in potential = - integral (vector E dot vector dl), dl is length element
So V-0 = -vector E dot integral(vector dl) from (0,0) to (2,2)

V= -(20i ̂+30j ̂ ) . {(2,2)-(0,0)}
V= -(20,30) . (2,2)
V= -(40+60)
V= -100V

Electrostatics> An electric field E=(20i ^ + 30j ^ ) N/C ...

An electric field E=(20i^{^} + 30j^{^}) N/C exists in space. If electric potential at origin is taken to be 50 V, then electric potential at (2m,2m) is?

Shillpa Nair , 5 Years ago

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Electrostatics> An electric field E=(20i ^ + 30j ^ ) N/C ...

An electric field E=(20i^ + 30j^) N/C exists in space. If electric potential at origin is taken to be 50 V, then electric potential at (2m,2m) is?

Shillpa Nair , 5 Years ago

Arun

Provide a better Answer & Earn Cool Goodies

LIVE ONLINE CLASSES

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