An alpha particle moves toward a rest nucleus if k.e is 10 MeV and atomic no of nucleus is 50.the closest approach will be
Abhishek , 7 Years ago
Grade 12
2 Answers
Nandakumar
Last Activity: 7 Years ago
I think you have to equate kinetic and potential energy ie 1/2mv2=1/4pi€×2Ze2/r r is the distance of closest approach by substituting the values you get r=14.4×10-15 m
Pratham Savjani
Last Activity: 5 Years ago
Here we need to equate Potential Energy and Kinetic energy.
Therefore
K.E=P.E
1/2 mv^2 = kq1q2/r
r=kq1q2/0.5mv^2
r=9*10^9*2e*50e/10 mev
Search the value of mev in terms of joules and substitute it.
e=1.6*10^-19
You will get answer as 1.44*10^-14
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free