An alpha particle moves toward a rest nucleus if k.e is 10 MeV and atomic no of nucleus is 50.the closest approach will be

Question

Nandakumar · Answer

I think you have to equate kinetic and potential energy ie 1/2mv2=1/4pi€×2Ze2/r r is the distance of closest approach by substituting the values you get r=14.4×10-15 m

Pratham Savjani · Answer

Here we need to equate Potential Energy and Kinetic energy. Therefore K.E=P.E 1/2 mv^2 = kq1q2/r r=kq1q2/0.5mv^2 r=9*10^9*2e*50e/10 mev Search the value of mev in terms of joules and substitute it. e=1.6*10^-19 You will get answer as 1.44*10^-14

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An alpha particle moves toward a rest nucleus if k.e is 10 MeV and atomic no of nucleus is 50.the closest approach will be

An alpha particle moves toward a rest nucleus if k.e is 10 MeV and atomic no of nucleus is 50.the closest approach will be

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An alpha particle moves toward a rest nucleus if k.e is 10 MeV and atomic no of nucleus is 50.the closest approach will be

An alpha particle moves toward a rest nucleus if k.e is 10 MeV and atomic no of nucleus is 50.the closest approach will be

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