Kevin Nash
Last Activity: 10 Years ago
Hello Student,
Please find the answer to your question
. (a,b,c,d)
Electric field inside a spherical metallic shell with charge on the surfaceis always zero. Therefore option [a] is
correct.
When the sells are connected with a thin metal wire then electric potentials will be equal, say V
∴ 1/ 4πϵ0 QA/RA = 1 / 4 πϵ0 QB/RB = V
As RA> RB therefore QA> AB option [b] is also correct.
As σA/σB QA/4πR2A/QB/4πR2B = R2B / R2A x 4πϵ0 RAV / 4πϵ0 RAV
∴σA/σB = RB / RA
Option (c) is also correct
Also EA = σA/ σB = RB/RA< 1 ∴ EA< EB
Option (d) is also correct
Thanks
Kevin Nash
askIITians Faculty
