Electrostatics> A spherical metal shell A of radius R A a...

A spherical metal shell A of radius R_A and a solid metal sphere B of radius R_B (_A) are kept far apart and each is given charge ‘+Q’, Now they are connected by a thin metal wire Then

(a) E_A^inside = 0
(b) Q_A> Q_B
(c) σ A/ σB = R_B/R_A
(d) E_A^onsurface_B^onsurface

Radhika Batra , 10 Years ago

Grade 11

1 Answers

Kevin Nash

Last Activity: 10 Years ago

Hello Student,

Please find the answer to your question

. (a,b,c,d)

Electric field inside a spherical metallic shell with charge on the surfaceis always zero. Therefore option [a] is

correct.

When the sells are connected with a thin metal wire then electric potentials will be equal, say V

∴ 1/ 4πϵ₀ Q_A/R_A = 1 / 4 πϵ₀ Q_B/R_B = V

As R_A> R_B therefore Q_A> A_B option [b] is also correct.

As σA/σB QA/4πR²A/QB/4πR²_B = R²_B / R²_A x 4πϵ₀ R_AV / 4πϵ₀ R_AV

∴σ_A/σ_B = R_B / R_A

Option (c) is also correct

Also E_A = σ_A/ σ_B = R_B/R_A< 1 ∴ E_A< E_B

Option (d) is also correct

Thanks
Kevin Nash
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Electrostatics> A spherical metal shell A of radius R A a...

A spherical metal shell A of radius RA and a solid metal sphere B of radius RB (A) are kept far apart and each is given charge ‘+Q’, Now they are connected by a thin metal wire Then (a) EAinside = 0(b) QA> QB(c) σ A/ σB = RB/RA(d) EAonsurfaceBonsurface

Radhika Batra , 10 Years ago

Kevin Nash

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