Navjyot Kalra
Last Activity: 10 Years ago
(a,b,c,d)
Electric field inside a spherical
metallic shell with charge on the surface is always zero. Therefore option [a]
is
correct.
When the sells are connected with
a thin metal wire then electric potentials will be equal, say V
? 1/ 4p
?0 QA/RA
= 1 / 4 p ?0 QB/RB
= V
As RA > RB
therefore QA > AB option [b] is also correct.
As sA/sB
QA/4pR2A/QB/4pR2B
= R2B / R2A x 4p
?0 RAV
/ 4p ?0 RAV
? sA/sB = RB
/ RA
Option (c) is also correct
Also EA = sA/ sB = RB/RA
< 1 ? EA < EB
Option (d) is also correct