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(a,b,c,d)
Electric field inside a spherical metallic shell with charge on the surface is always zero. Therefore option [a] is
correct.
When the sells are connected with a thin metal wire then electric potentials will be equal, say V
? 1/ 4p ?0 QA/RA = 1 / 4 p ?0 QB/RB = V
As RA > RB therefore QA > AB option [b] is also correct.
As sA/sB QA/4pR2A/QB/4pR2B = R2B / R2A x 4p ?0 RAV / 4p ?0 RAV
? sA/sB = RB / RA
Option (c) is also correct
Also EA = sA/ sB = RB/RA < 1 ? EA < EB
Option (d) is also correct
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