Aditya
Last Activity: 7 Years ago
Let potential at infinity equals to 0.R-radius of shell, r-radius of sphere Now, in first case, sphere has potential kQ/r. Shell has potential 0. Therefore,pd is kQ/r. Now after giving -3Q to the shell, potential of sphere becomes( kQ/r )-(3kQ/R). Potential of shell is -3 kQ/R. Therefore pd is (kQ/r - 3kQ/r)-(-3kQ/r)=kQ/r. That is, it remains same