# a rod of length l carries a charge q uniformly distributed over it. find the electric field intensity at a point charge a on the perpendicular bisector of the rod.

Khimraj
3007 Points
3 years ago
E = 4QL*sin(L/2)/aL
But i don’t know how to send photo here.
You can get using integration
E = $\int_{-L/2}^{L/2}2*dE*cos\Theta$
where dE = K*(Q/L)*dx/(a2 + x2)
cos$\Theta$ = a/(a2 + x2)1/2