#### Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.

Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

# a rod of length l carries a charge q uniformly distributed over it. find the electric field intensity at a point charge a on the perpendicular bisector of the rod.

Grade:12

## 1 Answers

Khimraj
3007 Points
one year ago
correction answer is
E = 4QL*sin(L/2)/aL
But i don’t know how to send photo here.
You can get using integration
E = $\int_{-L/2}^{L/2}2*dE*cos\Theta$
where dE = K*(Q/L)*dx/(a2 + x2)
cos$\Theta$ = a/(a2 + x2)1/2

## ASK QUESTION

Get your questions answered by the expert for free