# A particle of mass 'm' carry a charge of '-q1' starts moving around a fixed charge q2 along a circular path of radius r. What will be the period of revolution?

Arun
25758 Points
3 years ago
Dear student

As we know

Fe=Centripital force

k*q1*q2/r2 = Mrw2  [w=omega]

w2= k*q1*q2/Mr3

(2Π/T )2= k*q1*q2/Mr3

T2 = 4ΠMr3/k*q1*q2

T = (4ΠMr3/k*q1*q2)1/2

In case of any difficulty, please feel free to contact.

Regards

Arun (askIITians forum expert)

Khimraj
3007 Points
3 years ago
Kq1*q2/r2 = mv2/r
v = $\sqrt{K*q1*q2/m*r}$
so T = 2$\pi$r/v = 2$\pi$r($\sqrt{m*r/K*q1*q2}$
Hope it clears.