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a particle of mass m and charge q is subjected to combined actionof gravity and a uniform horizontal electric field of strength E. it is projected from ground with speed v in the vertical plane parallel to the field at an angleN to the horizontal . what is the maximum distance the object can travel horizontally before striking ground.

ria , 10 Years ago
Grade 12
anser 2 Answers
Sher Mohammad

Last Activity: 10 Years ago

force on particle
F= qe i+-mg k
intial velocity, u=VcosN i+ VsinN k
at maximum height vertical velocity is zero,
0=VsinN- mgt=0
t=V SinN/mg
the time to come back to ground = 2t= 2VSinN/mg
distance travelled , s=ut+.5 a t^2= VcosN*2VSinN/mg+ .5*qE*(2VSinN/mg)^2

sher mohammad
b.tech, iit delhi

Yeshwanth Talwar

Last Activity: 7 Years ago

Tg 2 cos 2 sin 1 2 sin2v v qE v Rg mg   ⎛ ⎞⎛ ⎞   ⎜ ⎟⎜ ⎟ ⎝ ⎠⎝ ⎠0 tan2 dR mqd qE  ⇒   222 2 2max 2v R qE m g q Emg

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