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A parallel plate capacitor is made by stacking n equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is 'C' then the resultant capacitance is (a) (n+1) C (b) (n -1 )C (c) nC (d) C

A parallel plate capacitor is made by stacking n equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is 'C' then the resultant capacitance is
 
(a) (n+1) C
(b) (n -1 )C
(c) nC
(d) C

Grade:6

4 Answers

Navjyot Kalra
askIITians Faculty 654 Points
6 years ago

(b) As n plates are joined, it means (n-1) combination joined in parallel.

? resultant capacitance = (n – 1 ) C
Abhishek Mangla
24 Points
3 years ago
Each plate is taking part in the formation of two capacitors except the plates at the ends. These capacitors are in parallel and n plates form (n -1) capacitors.Thus, equivalent capacitance between A and B = (n -1) C
Deepak Sharma
16 Points
2 years ago
We know that when we connect 4 capacitors each of capacitance Calternately,it performs like 3 capacitors in parallel i.e.(4-1)C.So n capacitors will be equivalent to (n-1)C.
Kushagra Madhukar
askIITians Faculty 629 Points
9 months ago
Dear student,
Please find the answer to your question below.
 
When n equally spaced plates are stacked alternatively, a total of (n – 1) capacitors are formed which are all in parallel.
Hence, The equivalent capacitance will be
Ceq = (n – 1) C
Hence, option (b) will be correct.
 
Thanks and regards,
Kushagra

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