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A Horizontal electric field E = mg/q exists as shown in the figure and a mass m is attached at the end of a light rod. if mass m is released from the position as shown in the figure. find the angular velocity at the bottom-most position

A Horizontal electric field E = mg/q exists as shown in the figure and a mass m is attached at the end of a light rod. if mass m is released from the position as shown in the figure. find the angular velocity at the bottom-most position

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Grade:12th Pass

2 Answers

Gaurav Gupta
askIITians Faculty 686 Points
2 years ago
564-1019_New Doc 2018-06-25_3.jpg
Yash Chourasiya
askIITians Faculty 256 Points
11 months ago
Hello Student

According to the work energy theorem we have
We​ + Wg ​= ​(mv2)/2
We have work done by electrostatic force as
We​= qElsinθ
and work done by the gravitational force as
Wg​ = mg(l−lcosθ)
Thus we get
qElsinθ + mg(l−lcosθ) =​ (mv2)/2
Thus we get
mgsinθ + mgl − mglcosθ = ​(mv2)/2
asθ = 45o, we get
mgl =​ (mv2)/2
also as v = ωl
we get
ω =√ (2g/l)

Hence option B is correct.

I hope this answer will help you.

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