Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A charged particle of charge q and mass M is released from rest in a uniform magnetic field. neglecting the force of gravity, the kinetic energy of the charged particle after time t seconds

A charged particle of charge q and mass M is released from rest in a uniform magnetic field. neglecting the force of gravity, the kinetic energy of the charged particle after time t seconds

Question Image
Grade:12

1 Answers

Arun
25763 Points
3 years ago
Dear dipika
 
I have solved using the effect of gravity.
You can neglect g.
 
 

1) qE + mg = ma
a = qE/m + g

 

2) v = 0 + at

 

    v = (qE/m + g)t

 

 

 

3) K.E =1/2mv^2

 

        = (1/2)m [(qE/m + g)t]^2 Joule

Now 

Neglect g

Hence

K.E. = (1/2)* m * q² E² t²/m²

 = q² E² t²/2m

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free