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A charged particle of charge q and mass M is released from rest in a uniform magnetic field. neglecting the force of gravity, thekinetic energy of the charged particle after time t seconds

Dipika deori , 7 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 7 Years ago

Dear dipika
 
I have solved using the effect of gravity.
You can neglect g.
 
 

1) qE + mg = ma
a = qE/m + g

 

2) v = 0 + at

 

    v = (qE/m + g)t

 

 

 

3) K.E =1/2mv^2

 

        = (1/2)m [(qE/m + g)t]^2 Joule

Now 

Neglect g

Hence

K.E. = (1/2)* m * q² E² t²/m²

 = q² E² t²/2m

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