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A charge q is placed on the spehrical surface of radius r. Because of mutual repultion of the charged surface, the radius is increased to a larger value 2r. if p naught is the pressure of the atmosphere, what is the value of q?

A charge q is placed on the spehrical surface of radius r. Because of mutual repultion of the charged surface, the radius is increased to a larger value 2r. if p naught is the pressure of the atmosphere, what is the value of q?

Grade:11

1 Answers

ROSHAN MUJEEB
askIITians Faculty 829 Points
11 months ago
Dear Student
This surface expands until electrostatic pressure is equal to the atmospheric pressure . Electrostatic pressure is given as sigma^2/ 2 epsilon, where sigma is the charge density. Hope you got it

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