Electrostatics> A charge of mass m charge 2e is released ...

A charge of mass m charge 2e is released from rest in a uniform electric field of strength E .what is the time taken by it to travel a distance d in the field

priyal , 6 Years ago

Grade 12

3 Answers

Adarsh

Last Activity: 6 Years ago

Dear priyal ,

force on charge = 2eE … so acceleration of charge = 2eE/m.

now, by using s=ut+1/2at²

we get , d = ½.2eE/m.t² => t = ( md/eE )^1/2

Thanka and Regards

Adarsh

Eshan

Last Activity: 6 Years ago

Dear student,

The force acting on the charge is $F=qE=(2e)E$

Hence the acceleration of the particle= $a=\dfrac{F}{m}=\dfrac{2eE}{m}$

From the second equation of motion,

$d=ut+\dfrac{1}{2}at^2$
$\implies d=(0)(t)+\dfrac{1}{2}\dfrac{2eE}{m}t^2$

$\implies t=\sqrt{\dfrac{dm}{eE}}$

Giresh

Last Activity: 5 Years ago

A Proton of mass M charge e is released from rest in a uniform electric field of strength the time taken by A train travels a distance D in the electric field is √(2dm/eE)

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Electrostatics> A charge of mass m charge 2e is released ...

A charge of mass m charge 2e is released from rest in a uniform electric field of strength E .what is the time taken by it to travel a distance d in the field

priyal , 6 Years ago

Adarsh

Eshan

Giresh

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