Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A certain charge is to be divided into two parts (Q-q) and q. What is the relation Q to q if the two parts, placed a given distance apart, are to have a maximun Coulumb repulsion?
Force = K(Q-q)q/r^wNow Numerator = K(Q-q)q should be maximum Hence,q ahould be minium.Rherfore,dN/dq = k[Q-q-q] = 0Q – 2q = 0Q = 2q is tthe relation.
Find solution of question on doubt solving app Instasolv
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -