A capacitor of 60 C is connected to a 200 V suppl

Question

A capacitor of 60 C is connected to a 200 V supply and another capacitor of 30 C is connected to 100V. Find the charge and energy stored on each capacitor. Now these two capacitors are disconnected from the supply and are joined to each other such that positive plate of first is connected to the positive plate of second and similarly the negative plates of both are joined together. Find the Loss in energy of the system. Why does this loss occurs?

kaushik dey · Accepted Answer

FOR THIS TYPE OF PROBLEM GUIDING PRINCIPLE IS : CHARGE IS CONSERVED INITIAL CHARGE: 200X60+30X100= 15X1000 AFTER CHANGING CONFIGURATION BOTH CAPACITANCE IN PARALLELSO EQUIVALENT CAP= 90 LET COMMON TERMINAL VOLTAGE BE V AS CHARGE CONSERVED 90XV= 15000V= 15000/90= 500/3 ONCE THIS VOLTAGE IS FOUND CHANGE IN ENERGYCAN BE CALCUALTED BY USING ½ CV2FORMULA. PLEASE DUE IT YOURSELF LOSS OF ENERGY IS DUE TO ENEGRY LOSSES IN CHARGE RE-DISTRIBUTION BETWEEN CAPACITORS.

Electrostatics> A capacitor of 60 C is connected to a 200...

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Electrostatics> A capacitor of 60 C is connected to a 200...

Ayush , 6 Years ago

kaushik dey

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