Vikas TU
Last Activity: 7 Years ago
Dear Student,
Charge of one drop=5C
Charge on 64 drops=64x5=320C (because charge is always conserved)
Volume would be same
Volume of the larger drop= Volume of 64 drops combined
=>4πR
3/3=64x4xπr
3/3
=>R=8cm
Potential=kq/R
=kx320/8
=40k V
=356x10
9 V.
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)