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two concentric rings are placed in gravity free region in yz plane. one of radius carries charge+Q and second of radius 4r carries charge -8Q distributed uniformly over it.find minimum velocity with which a point charge of mass m and charge -Q be projected from a point a istance 3r from centre of ring on its axis so that it will reach to the centre of ring?

shefali sharma , 16 Years ago
Grade 12
anser 1 Answers
Askiitians Tutor Team

To solve this problem, we need to analyze the forces acting on the point charge as it moves towards the center of the concentric rings. The setup consists of two rings: one with a positive charge +Q and a larger one with a negative charge -8Q. The goal is to find the minimum velocity required for a point charge of mass m and charge -Q, projected from a distance of 3r along the axis of the rings, to reach the center of the rings.

Understanding the Electric Field

First, let's consider the electric field generated by the two rings. The electric field due to a charged ring at a point along its axis can be calculated using the formula:

  • E = (k * Q * z) / (z^2 + R^2)^(3/2)

Where:

  • E = electric field strength
  • k = Coulomb's constant
  • Q = charge of the ring
  • z = distance from the center of the ring along the axis
  • R = radius of the ring

Calculating the Electric Fields

For the ring with charge +Q (radius r), at a distance z from the center (where z = 3r initially), the electric field is:

  • E_1 = (k * Q * 3r) / (9r^2 + r^2)^{3/2} = (k * Q * 3r) / (10r^2)^{3/2} = (3kQ) / (10√10) r^2

For the larger ring with charge -8Q (radius 4r), at the same distance z = 3r, the electric field is:

  • E_2 = (k * (-8Q) * 3r) / (9r^2 + (4r)^2)^{3/2} = (-24kQ) / (25√25) r^2 = (-24kQ) / (125) r^2

Net Electric Field

The total electric field at the point where the charge -Q is projected is the sum of the two fields:

  • E_net = E_1 + E_2 = (3kQ / (10√10) r^2) - (24kQ / 125 r^2)

To simplify this, we need a common denominator:

  • E_net = (3kQ * 125 - 24kQ * 10√10) / (1250√10) r^2

Force on the Point Charge

The force acting on the point charge -Q due to the electric field is given by:

  • F = -Q * E_net

Substituting E_net into this equation gives us the force acting on the charge as it approaches the center of the rings.

Energy Considerations

To find the minimum velocity required, we can use the conservation of energy principle. The initial kinetic energy (KE) plus the initial potential energy (PE) must equal the final potential energy when the charge reaches the center of the rings:

  • KE_initial + PE_initial = PE_final

At the center, the potential energy is at a maximum due to the electric fields. The potential energy can be calculated using:

  • PE = -Q * V

Where V is the electric potential at the center of the rings. The potential at the center due to both rings can be calculated and substituted into the energy equation.

Final Calculation

After substituting all values and solving for the initial velocity, we can derive the minimum velocity required for the charge -Q to reach the center of the rings. This involves some algebraic manipulation and solving for v in the kinetic energy equation:

  • v = √(2 * (PE_final - PE_initial) / m)

By plugging in the values for potential energies calculated earlier, we can find the minimum velocity needed for the charge to reach the center of the rings.

In summary, the problem involves understanding electric fields, forces, and energy conservation principles to find the required velocity for the charge to reach the center of the rings. Each step builds upon the previous one, leading to a comprehensive understanding of the dynamics involved in this electrostatic scenario.

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