Kushagra Madhukar
Last Activity: 4 Years ago
Hello student
As we know total electric flux given by a point charge Q = Q/ε0
this flux is equally distributed in a solid angle of 4π
Now, if a disk makes an angle θ with the axis of charge, the solid angle covered by the disk
Ω = 2π(1- cosθ)
Hence electric flux through disk, ɸ = Q/4πε0 x 2π(1- cosθ) = Q/2ε0 x (1 – cosθ)
Given, this flux is ¼ of the flux given by charge Q
Hence,
Q/2ε0 x (1 – cosθ) = Q/4ε0
or, cosθ = ½
or, θ = 60o
Hence, b/R = cos60o
or, b = R/2
or, R = 2b
or, b = (b2 + r2)1/2/2
or, 4b2 = b2 + r2
or, r2 = 3b2
or, r = √3 b
Hope it helps
Regards,
Kushagra