Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Force of attraction btw two point charges Q and -q separated by d metre is F when these charges are placed on two identical spheres of radius R=0.3d whoese centre are d metre apart the force of attraction btw them is

Force of attraction btw two point charges Q and -q separated by d metre is F when these charges are placed on two identical spheres of radius R=0.3d whoese centre are d metre apart the force of attraction btw them is

Grade:12

1 Answers

Rasika
15 Points
2 years ago
FFe=k*Q*-Q/d^2 F=k*Q*-Q/1.6d^2 F=Fe/1.6 Less than Fe therefore the force is less than the force on the two point charges 
R=0.3d
Distance between two sphere is 0.4d

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free