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Grade 12Electrostatics

Force of attraction btw two point charges Q and -q separated by d metre is F when these charges are placed on two identical spheres of radius R=0.3d whoese centre are d metre apart the force of attraction btw them is

pallavi pradeep bhardwaj

16 Years agoGrade 12

1 Answer

Rasika

7 Years ago

F $Fe=k*Q*-Q/d^2 F=k*Q*-Q/1.6d^2 F=Fe/1.6 Less than Fe$ therefore the force is less than the force on the two point charges

R=0.3d

Distance between two sphere is 0.4d

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