# a 10cm long rod carries a charge of 50 micro coulomb distributed uniformly along its length .find the magnitude of the electric field at a point 10cm from both the ends of the rod

Arun Kumar IIT Delhi
7 years ago
10 cm from both ends means symmetrical and distance from center
$\small z=\sqrt3/2*10$
Now since its symmetric so the component along the wire length will be cancelled so the only component that remains is perpendicular to plane.
$\small E_{perpendicular}=2k\lambda l/(z(z^2+(l/2)^2))$
Where l is length of wire.
Thanks & Regards
Arun Kumar
IIT Delhi
Rishi Sharma
one year ago
Dear Student,

10 cm from both ends means symmetrical and distance from center
z = √3/2*10
Now since its symmetric so the component along the wire length will be cancelled so the only component that remains is perpendicular to plane.
Eperpendicular = 2klλ / (z(z^2 + (l/2)^2))
Where l is length of wire.

Thanks and Regards