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Grade 11Electrostatics

(1) Two particles, each of mass m and carrying charge Q, are separated by some distance.If they are in equilibrium under mutual gravitational and electrostatic forces,then Q/m (in C/Kg) is of the order of

(a) 10-5

(b) 10-10

(c) 10-15

(c) 10-20

Profile image of Nimish Singh
13 Years agoGrade 11
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5 Answers

Profile image of Mujahid Ahmed
13 Years ago

K Q2/r2 = Gm2/r2

Q2/m2 = G/K

= 6,6 x 10-11/9 x 109

= 10-20

 

Approve if i helped :)

Profile image of Abhishekh kumar sharma
13 Years ago

10^-15

Profile image of anurag hundal
13 Years ago

guess its c!

Profile image of Jatin Singh
10 Years ago
repulsive electrostatic force:                         attractive gravitational force:
F1=kQ^2/r^2                                                   F2=Gm^2/r^2
 
for equilibrium :F1=F2
kQ2/r2=Gm2/r2
=> Q/m = (6.6*10^-11/9*10^9)1/2
=> Q/m=0.8*10-10
Hence, ORDER OF Q/m=10-10
 
Profile image of Kushagra Madhukar
5 Years ago
Dear student,
Please find the solution to your problem below.
repulsive electrostatic force(since charges are same in magnitude and sign):            
F1 = kQ2/r2                                                 
attractive gravitational force:
F2 = Gm2/r2
for equilibrium :F1 = F2
kQ2/r2 = Gm2/r2
=> Q/m = (6.6*10-11/9*109)1/2
=> Q/m=0.8*10-10
Hence, ORDER OF Q/m=10-10
Hence (b) is the correct option.
 
Hope it helps.
Thanks and regards,
Kushagra