Electrostatics> Coloumb's Law...

(1) Two particles, each of mass m and carrying charge Q, are separated by some distance.If they are in equilibrium under mutual gravitational and electrostatic forces,then Q/m (in C/Kg) is of the order of

(a) 10^-5

(b) 10^-10

(c) 10^-15

(c) 10^-20

Nimish Singh , 12 Years ago

Grade 11

5 Answers

Mujahid Ahmed

K Q²/r² = Gm²/r²

Q²/m² = G/K

= 6,6 x 10^-11/9 x 10⁹

= 10^-20

Approve if i helped :)

Last Activity: 12 Years ago

Abhishekh kumar sharma

10^-15

Last Activity: 12 Years ago

anurag hundal

guess its c!

Last Activity: 12 Years ago

Jatin Singh

repulsive electrostatic force: attractive gravitational force:

F₁=kQ^2/r^2 F₂=Gm^2/r^2

for equilibrium :F₁₌F₂

kQ²/r²=Gm²/r²

=> Q/m = (6.6*10^-11/9*10^9)^1/2

=> Q/m=0.8*10^-10

Hence, ORDER OF Q/m=10^-10

Last Activity: 9 Years ago

Kushagra Madhukar

Dear student,

Please find the solution to your problem below.

repulsive electrostatic force(since charges are same in magnitude and sign):

F₁ = kQ²/r²

attractive gravitational force:

F₂ = Gm²/r²

for equilibrium :F₁= F₂

kQ²/r²= Gm²/r²

=> Q/m = (6.6*10^-11/9*10⁹)^1/2

=> Q/m=0.8*10^-10

Hence, ORDER OF Q/m=10^-10

Hence (b) is the correct option.

Hope it helps.

Thanks and regards,

Kushagra

Last Activity: 5 Years ago

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Electrostatics> Coloumb's Law...

(1) Two particles, each of mass m and carrying charge Q, are separated by some distance.If they are in equilibrium under mutual gravitational and electrostatic forces,then Q/m (in C/Kg) is of the order of (a) 10-5 (b) 10-10 (c) 10-15 (c) 10-20

Nimish Singh , 12 Years ago

Mujahid Ahmed

Abhishekh kumar sharma

anurag hundal

Jatin Singh

Kushagra Madhukar

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(1) Two particles, each of mass m and carrying charge Q, are separated by some distance.If they are in equilibrium under mutual gravitational and electrostatic forces,then Q/m (in C/Kg) is of the order of

(a) 10^-5

(b) 10^-10

(c) 10^-15

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