Grade 12Electrostatics

A charged particle of charge q and mass m is released from rest in an uniform electric feild E.The kinetic energy of the charged particle after time"t" seconds is

Rohan Kumar

13 Years agoGrade 12

5 Answers

Vikas TU

13 Years ago

1) qE + mg = ma
a = qE/m + g

2) v = 0 + at

v = (qE/m + g)t

3) K.E =1/2mv^2

= 1/2m [(qE/m + g)t]^2 Joule

Chetan Mandayam Nayakar

13 Years ago

force=qE,impulse=qEt=momentum=p, k.e.=p²/2m

dhaval Rohilla

8 Years ago

If the effect of gravity is neglected then, ma =qE. Then from kinematic eqn v=u+at as the motion starts from rest then u=0,putting the value of v^2 in the kinetic energy formula we get E^2q^2t^2 \ 2m

Udit Thacker

7 Years ago

The particle here will perform uniformly accelerated motion as it is acted upon by a constant electrostatic force qE. The acceleration of the particle is thus qE/m. Now just apply the equation of motion v = u + at .

initial velocity u=0

acceleration a=qE/m

by v=u+at

v=0 + (qE/m)t

v= (qE/m)t

KE= ½(mv²)

KE= 1/2m(qE/m)²t²

Yash Chourasiya

6 Years ago

Dear Student

A force is generated because of the elective field
F = qE
⇒ a = qE/m.

As the particle starts from rest and acceleration is constant applying equation of motion.
V = u + at
V = 0 + qEt/m
V = qET/m
Then,KE = 1/2(mv²)
= (1/2)m(qEt/m)²
= (q²E²t²)/2m

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya