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# Force of attraction between two co axial short electric dipoles

Biswajit Das
6 years ago
We know that, Coulomb force, F = Kq1q2/d2
Dipole moment, p =qd.
So, q1= p1/d and q2= p2/d
Putting these values in Coulomb force, we get,
F = K(p1/d) (p2/d)/d2
= K (p1) (p2)/d4
Therefore, Force is varies fourth power of distance.
Ajeet Tiwari
one year ago
hello students

We know that, Coulomb force, F = Kq1q2/d2 Dipole moment, p =qd. So, q1= p1/d and q2= p2/d Putting these values in Coulomb force, we get, F = K(p1/d) (p2/d)/d^2 = K (p1) (p2)/d^4 Therefore, Force is varies fourth power of distance.

Hope it helps
Thankyou

Yash Chourasiya
one year ago
Dear Students

We know that, Coulomb force, F = Kq1q2/d2
Dipole moment, p = qd.
So, q1= p1/d and q2 = p2/d
Putting these values in Coulomb force, we get,
F = K(p1/d) (p2/d)/d2
= K (p1) (p2)/d4
Therefore, It is clearly seen that Force varies with fourth power of distance.